Units and units conversion
The International System of Units, or simply SI, is the most widely used system of units. In the SI system, there are seven base units and numerous derived units. Derived units are just combinations of the base units.SI base units
The following are the seven base units.| Physical quantity | Unit name | Unit symbol |
|---|---|---|
| length | meter | $m$ |
| mass | kilogram | $kg$ |
| time | second | $s$ |
| electric current | ampere | $A$ |
| temperature | kelvin | $K$ |
| amount of substance | mole | $mol$ |
| luminous intensity | candela | $cd$ |
SI common derived units
The following are the most commonly used derived units in Physics 1.| Physical quantity | Unit |
|---|---|
| area | $m^2$ |
| volume | $m^3$ |
| speed | $m/s$ |
| velocity | $m/s$ |
| acceleration | $m/s^2$ |
| force | $N$ |
| work | $J$ |
| energy | $J$ |
| power | $W$ |
| momentum | $kg.m/s$ or $N.s$ |
| impulse | $kg.m/s$ or $N.s$ |
| spring constant | $N/m$ |
| angle | $rad.$ |
| angular velocity | $rad./s$ |
| angular acceleration | $rad./s^2$ |
| torque | $N.m$ |
| moment of inertia | $kg.m^2$ |
| angular momentum | $kg.m^2/s$ |
| stress | $N/m^2$ |
| Young's modulus | $N/m^2$ |
| shear modulus | $N/m^2$ |
| bulk modulus | $N/m^2$ or $Pa$ |
| strength of materials | $N/m^2$ or $Pa$ |
| density | $kg/m^3$ |
| pressure | $N/m^2$ or $Pa$ |
| frequency | $Hz$ or $s^{-1}$ |
| intensity | $W/m^2$ |
| heat | $J$ |
| specific heat | $J/kg.K$ |
| latent heat | $J/kg$ |
| thermal conductivity | $Wm^{-1}K^{-1}$ |
| entropy | $J/K$ |
Unit conversion
Sometimes you may need to convert a unit from one system of units to another. That is from another system of units to SI, or from SI to another system. To do unit conversion, you need a conversion factor, which relates the old unit and the new unit.Conversion is nothing but dividing out the unit that you don't want and multiplying in the unit that you do want.
Example 1: What is the height of a $48 \,ft$ building in $m$?
Solution: You are converting from $ft$ to $m$. The conversion factor for that is$1\: ft=0.3048\: m$
Take the original number and multiply with $1$.
$48 \,ft=48 \,ft \times 1$
The unit that you want is $m$, and the one you do not want is $ft$, which you should cancel out. So, you need to bring the $ft$ to the denominator in the conversion factor.
In the conversion factor, the unit $ft$ is on the left hand side. So, divide both sides of the conversion factor by everything on the left hand side ($1 ft$):
$1\:=\dfrac{0.3048\:m}{1 ft}$
Now, replace the $1$ in the previous equation with this $1$,
$48ft = 48ft\times 1$
$=48ft\times \dfrac{0.3048m}{1 ft}$
Canceling out $ft$,
$=48\cancel{ft}\times \dfrac{0.3048m}{1 \cancel{ft}}$
$=14.6304 m$
Rounding to correct number of significant figures,
$\boxed{48ft = 15 m}$
Note that when you are doing a conversion, round the final result to the same number of significant figures as the original number. Don't worry about the numbers in the conversion factor, as we consider them exact, with an infinite number of significant figures.
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In the previous problem, the quantity height has only one base unit, $ft$, which we converted to $m$. If you want to convert a quantity that has more than one unit (a combination of units), then you will need more than one conversion factor, but the same procedure applies.
Example 2: The speed of a car is $75 \,km/h$. What is its speed in $m/s$?
Solution:
Here, there are two units: $km$ and $h$. And you need to convert $km$ to $m$ and $h$ to $s$. So, you need two conversion factors:$1\:km=1000\:m$
and$1\:h=3600\:s$
Since there are two base units in the quantity, you should multiply the original number by two $1$'s and later replace these with the conversion factors.
$75\:km/h=75\:km/h\times 1 \times 1$
Since $km$ is in the numerator, you need to have it in the denominator in the conversion factor to cancel it out. And the $h$ is in the denominator, so you need to have it in the numerator in the conversion factor.
So, you have,
$1=\dfrac{1000\,m}{1\,km}$
and$\dfrac{1\,h}{3600\,s}=1$
Replacing the $1$'s with these values, we get,
$75\:km/h=75\:km/h\times \dfrac{1000\:m}{1\:km} \times \dfrac{1\:h}{3600\:s}$
Canceling out $km$ and $h$,
$75\:km/h=75\:\cancel{km}/\cancel{h}\times \dfrac{1000\:m}{1\:\cancel{km}} \times \dfrac{1\:\cancel{h}}{3600\:s}$
Simplifying and rounding to the correct number of significant figures,
$\boxed{75\:km/h=21\: m/s}$
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There are physical quantities with units having exponents. For example, the SI unit of density is $kg/m^3$. The following example will help you to convert such quantities from one system of units to another.
Example 3: In the cgs system, the unit of density is $g/cm^3$ ($g$ is grams). The density of mercury is $13.6 \, g/cm^3$. What is the density of mercury in the SI unit?
Solution:
In SI, the unit of density is $kg/m^3$. So, we need to convert $g$ to $kg$ and $cm$ to $m$ (i.e., $cm^3$ to $m^3$).
The conversion factors (from the table at the bottom of this page) are
$1 \,kg = 1000\,g$ and
$100 \,cm = 1\,m$
Since there are two units to convert, multiply the given number by two 1's. Since one of the units has an exponent of 3, put that exponent on one of the 1's:
$13.6\,g/cm^3 = 13.6\,g/cm^3\times 1\times 1^3$
The unit $g$ is in the numerator, so to cancel it, bring it to the denominator in the conversion factor. And since the unit $cm$ is in the denominator, it should be in the numerator in the conversion factor. i.e.,
$\dfrac{1\,kg}{1000\,g}=1$ and
$\dfrac{100\,cm}{1\,m}=1$
Substituting these in place of 1's in the equation:
$13.6\,g/cm^3 = 13.6\,g/cm^3\times \dfrac{1\,kg}{1000\,g} \times \left(\dfrac{100\,cm}{1\,m}\right)^3$
Canceling $g$ and $cm^3$,
$13.6\,g/cm^3 = 13.6\,\cancel{g}/\cancel{cm^3}\times \dfrac{1\,kg}{1000\,\cancel{g}} \times \left(\dfrac{100\,\cancel{cm}}{1\,m}\right)^3$
$= \dfrac{13.6}{1000}\times 100^3\,kg/m^3$
$= 1.36\times 10^4\,kg/m^3$
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Table of conversion factors
| Non-SI unit | SI unit | Conversion factor |
|---|---|---|
| $cm$ (centimeter) | $m$ | 100 $cm = $1 $m$ |
| $1km$ | $m$ | $1\:km=1000\:m$ |
| $in.$ (inch) |
$m$ | $1\:in.=0.0254\:m$ |
| $ft$ (feet) |
$m$ | $1\:ft = 0.3048\: m$ |
| $\mu m$ (micrometer) |
$m$ | $1\: \mu m = 1\times 10^{-6}\: m$ |
| $mi$ (mile) |
$m$ | $1\: mi = 1609\: m$ |
| $nm$ (nanometer) |
$m$ | $1\: nm = 10^{-9}\: m$ |
| $L$ (liter) |
$m^3$ | $1\:L = 10^{-3}\: m^3$ |
| $g$ (gram) |
$Kg$ | $1\: g=10^{-3}\:kg$ |
| $lb$ (pound) |
$kg$ | $1\: lb = 0.4536\: kg$ |
| $°$ (degree) |
$rad.$ | $1°=\dfrac{2\pi}{180}\:rad.$ |
| $g/cm^3$ | $kg/m^3$ | $1\: g/cm^3 = 10^{3}\: kg/m^3$ |
| $h$ (hour) |
$s$ | $1\: h = 3600\: s$ |
| $mph$ (miles per hour) |
$m/s$ | $1\: mph = 0.447\: m/s$ |
| $lbf$ (pound-force) |
$N$ | $1\: lbf = 4.4482\: N$ |
| $atm$ |
$Pa$ | $1\: atm = 1.01325 \times 10^5\: Pa$ |
| $bar$ | $Pa$ | $1\: bar = 10^5\: Pa$ |
| $torr$ | $Pa$ | $1\: torr = 133.32 \:Pa$ |
| $mmHg$ |
$Pa$ | $1\: mmHg = 133.32\: Pa$ |
| $BTU$ |
$J$ | $1 \:BTU = 1.055\times 10^3\: J$ |
| $P$ (poise) |
$Pa.s$ | $1\:P=0.1\:Pa.s$ |
| $G$ (gauss) |
$T(tesla)$ | $1\:G= 10^{-4}\: T$ |
| $°C$ (degree celsius) |
$K$ | $T$ ($K$)$=T$ (°$C$)$+273.15$ |